Questions on Distribution

Study the pie-chart and answer the question. Distribution (degree-wise) of the number of employees of a company working in 5 departments A, B, C, D and E. The number of employees working in department C is what percentage more than the total number of employees working in D and E? (Your answer should be correct to one decimal place.)

Study the pie chart and answer the question. Distribution of the number of employees of a companyworking in 5 department A, B , C, D and E IF the total number of employees are 3200.If the total number of employees working in deparments A and B exceeds the number of employees in department C by x, then x lies between:

Study the pie chart and answer the question Distribution of the number of employees of a companyworking in 5 departments A B C D and E If the ratio of male employees and female employees working in department D is 4:5 and that in department E is 9:11 then what is the ratio of the total male employees in D and E to the number of employees in B.

Study the pie chart and answer the question. Distribution of the number of employees of a companyworking in 5 department A, B , C, D and E the number of employees working in department C is what percentage more than the total number of employees working in D and E?

Study the pie-chart and answer the question. Distribution (degree wise ) of the total number of employeesofa company in its five offices A,B,C,D&E. Total Number of employees = 9200 Total number of employees of the company in offices C and D exceeds the number of employees in office B by x, where X lies between:

Questions based on Distribution and Division amongst group || Arrangement OF like groups

Questions based on Distribution & Division amongst group|| Arrangement OF like groups

Questions|Centre Of Mass Of Continous Mass Distribution|Cavity Problems

Questions|Important Points About Centre Of Mass|Centre Of Mass Of Continuous Mass Distribution|Centre Of Mass Of Uniform Rod

NCERT Questions|Continuous Charges Distribution|Electric Field Due To Uniformly Charged Wire