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Calculate the heat energy required to ra...

Calculate the heat energy required to raise the temperature of 2 kg of water from `10^@C` to `50^@C`. Specific heat capacity of water is `4200 JKg^(-1) K^(-1)`

Text Solution

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Given m = 2 Kg, `DeltaT=(50-10)=40^(@)C` In terms of Kelvin, `DeltaT=(323.15-283.15)=40" K, "C=4200" J Kg"^(-1)"K"^(-1)`
`:.` Heat energy required, `Q=mxx CxxDeltaT=2xx4200xx40=3,36,00J`
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