Calculate the ratio of energies of photon produced due to transition of electron of hydrogen atom from its (i) second permitted energy level to the fist level and (ii) highest permitted energy level to the second permitted level.

Explanation

`(i) DeltaE_(1) = E_(2) - E_(1)`
`= (-13.6)/((2)^(2)) - (-13 .6)`
`= (-13.6)/(4) + 13.6`
`10.2 ` eV
(ii) `Deltae_(2) = (13.6)/((oo)^(2)) = ((-13.6))/((2)^(2))`
`= 0+ (13.6)/(4)`
`= 3.4 eV`
`:. (DeltaE_(1))/(DeltaE_(2))= (10.2)/(3.4) =3 `