0.05 M NaOH solution offers a resistance of 32 ohms in a conductivity cell at 298K. If the cell constant of the cell is `0.376 cm^(-1)`, Calculate the molar conductance of NaOH solution.

Define' specific and equivalent conductance'. How are they related ? 0.05 M NaOH solution offered a resistance of 31.6 ohm in a conductivity cell at 298 K . If the cell constant of the cell is 0.376cm^-1 , calculate the molar conductance of the NaOH solution.

The resistance of a conductivity cell when filled with 0.05M solution of an electrolyte x is 100 Omega at 40^(@)C . The same conductivity cell filled with 0.01M solution of electrolyte y has a resistance of 50 Omega . The conductivity of 0.05 M solution of electrolyte x is 1.0 xx 10^(-4) S cm^(-1) . Calculate (i) cell constant (ii) conductivity of 0.01 M solution (iii) molar conductivity of 0.01 M solution

A 0.1N solution of NaCl has a specific conductance of 0.00112 ohm^-1 cm^-1 . Calculate the equivalent conductance of the solution.

The conductivity of 0.20 M solution of KCl at 298 K is 0.248S cm^(-1) . Calculate its molar conductivity.

At a certain temperature the specific conductance of 0.40M KCl solution is 4.96xx10^-2 ohm^-1cm^-1 . Calculate its molar conductance.