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If the numerator ad the denominator of a...

If the numerator ad the denominator of a fraction is increased by 3 and 4 repectively, the fraction becomes `(4)/(5)` and if the numerator and denominator of the same fraction are increased by 7 and 3 respectively, the fraction becomes `(4)/(3)`. What is the original fraction ?

A

`(4)/(5)`

B

`(2)/(3)`

C

`(5)/(6)`

D

`(6)/(7)`

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The correct Answer is:
To find the original fraction given the conditions in the problem, we can follow these steps: ### Step 1: Define the Variables Let the original fraction be represented as \( \frac{x}{y} \), where \( x \) is the numerator and \( y \) is the denominator. ### Step 2: Set Up the First Equation According to the first condition, if the numerator is increased by 3 and the denominator by 4, the fraction becomes \( \frac{4}{5} \): \[ \frac{x + 3}{y + 4} = \frac{4}{5} \] Cross-multiplying gives: \[ 5(x + 3) = 4(y + 4) \] Expanding this leads to: \[ 5x + 15 = 4y + 16 \] Rearranging gives us the first equation: \[ 5x - 4y = 1 \quad \text{(Equation 1)} \] ### Step 3: Set Up the Second Equation According to the second condition, if the numerator is increased by 7 and the denominator by 3, the fraction becomes \( \frac{4}{3} \): \[ \frac{x + 7}{y + 3} = \frac{4}{3} \] Cross-multiplying gives: \[ 3(x + 7) = 4(y + 3) \] Expanding this leads to: \[ 3x + 21 = 4y + 12 \] Rearranging gives us the second equation: \[ 3x - 4y = -9 \quad \text{(Equation 2)} \] ### Step 4: Solve the System of Equations Now we have the system of equations: 1. \( 5x - 4y = 1 \) 2. \( 3x - 4y = -9 \) We can eliminate \( y \) by subtracting Equation 2 from Equation 1: \[ (5x - 4y) - (3x - 4y) = 1 - (-9) \] This simplifies to: \[ 2x = 10 \] Dividing both sides by 2 gives: \[ x = 5 \] ### Step 5: Substitute to Find \( y \) Now substitute \( x = 5 \) back into Equation 1: \[ 5(5) - 4y = 1 \] This simplifies to: \[ 25 - 4y = 1 \] Rearranging gives: \[ 4y = 24 \] Dividing both sides by 4 gives: \[ y = 6 \] ### Step 6: Write the Original Fraction Now that we have \( x = 5 \) and \( y = 6 \), the original fraction is: \[ \frac{x}{y} = \frac{5}{6} \] ### Final Answer The original fraction is \( \frac{5}{6} \). ---
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