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Rubina could get equal number of Rs. 55 ...

Rubina could get equal number of Rs. 55 , Rs. 85 and Rs. 105 tickets for a movie. She spents Rs. 2,940 for all the tickets. How many of each did she buy ?

A

12

B

14

C

16

D

Can’t be determined

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we can follow these steps: ### Step 1: Define the Variables Let \( X \) be the number of tickets of each type that Rubina buys. Therefore, she buys \( X \) tickets of Rs. 55, \( X \) tickets of Rs. 85, and \( X \) tickets of Rs. 105. ### Step 2: Write the Equation The total cost of the tickets can be expressed as: \[ \text{Total Cost} = (\text{Number of Rs. 55 tickets} \times \text{Price of Rs. 55 ticket}) + (\text{Number of Rs. 85 tickets} \times \text{Price of Rs. 85 ticket}) + (\text{Number of Rs. 105 tickets} \times \text{Price of Rs. 105 ticket}) \] Substituting the values, we get: \[ 2940 = (55X) + (85X) + (105X) \] ### Step 3: Combine Like Terms Now, we combine the terms on the right side: \[ 2940 = 55X + 85X + 105X = (55 + 85 + 105)X = 245X \] ### Step 4: Solve for X Now we can solve for \( X \): \[ 245X = 2940 \] To find \( X \), divide both sides by 245: \[ X = \frac{2940}{245} \] ### Step 5: Calculate X Now, we perform the division: \[ X = 12 \] ### Conclusion Rubina bought 12 tickets of each type (Rs. 55, Rs. 85, and Rs. 105).
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