Calculate the work done to take an object of mass 20 kg to a height of 10 m.

Explanation

`m= 20 kg, s = 10 m`
`g = 9.8 m//s^(2)`
`therefore F = m.g`
`=20 xx (-9.8)`
(The negative sign is taken because the displacement is opposite to the direction of the force.)
`F=-196 N`
`therefore W = Fs`
`=-196xx10`
`W=-1960 J`
(The negative sign appears because the direction of force is opposite to the direction of displacement so that the work done is negative.)