A stone having a mass of 250 gm is falling from a height. How much kinetic energy does it have at the moment when its velocity is 2 m/s?

Explanation

`m = 250 g" "m=0.25 kg`
v=2 m/s
K.E. `=(1)/(2) mv^(2) =(1)/(2) xx0.25xx(2)^(2) =0.5 J`