Three resistors having resistances of `5 Omega`, `10 Omega` and `30 Omega` are connected in parallel and a potential difference of 12 V is applied across them. Obtain the current flowing through the circuit ang through individual resistors. What is the effective resistance in the circuit?

Explanation

`R_(1)=5 Omega, R_(2)=10 Omega and R_(3)= 30 Omega, V=12 V`
`I_(1) =(V)/(R_(1))=(12)/(5) =2.4 A`
`I_(2) =(V)/(R_(2))=(12)/(10) =1.2 A`
`I_(3) =(V)/(R_(3))=(12)/(30)=0.4 A`
`I=I_(1)+I_(2)+I_(3)=2.4+1.2+0.4=4.0 A`
`(1)/(R_(p)) =(1)/(R_(1))+(1)/(R_(2))+(1)/(R_(3))=(1)/(5)+(1)/(10)+(1)/(30) =(6+3+1)/(30) =(10)/(30) =(1)/(3)`
Effective resistance in the circuit `= 3 Omega` and the current flowing through the resistances `5 Omega, 10 Omega and 30 Omega` is 2.4 A, 1.2 A and 0.4 A respectively. The total current flowing through the circuit is 4 A.