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In DeltaABC and DeltaPQR, in a one to on...

In `DeltaABC and DeltaPQR`, in a one to one correspondence.
`(AB)/(QR) = (BC)/(PR) = (CA)/(PQ)`, then

A

` Delta PQR ~ Delta ABC `

B

` Delta PQR ~ Delta CAB `

C

` Delta CBA ~ Delta PQR `

D

` Delta BCA ~ Delta PQR `

Text Solution

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The correct Answer is:
B
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