Mahendra and Virat are sitting at a distance of 1 metre from each other. Their masses are 75 kg and 80 kg respectively. What is the gravitational force between them?

Explanation

`r = 1 m, m_(1) = 75 kg, m_(2) = 80 kg and G = 6.67 xx 10^(-11) Nm^(2)//kg^(2)`
According to Newton’s law
`F=(Gm_(1)m_(2))/(r^(2))`
`F=(6.67xx10^(-11)xx 75xx80)/(1^(2)) N`
`=4.002xx10^(-7) N`
The gravitational force between Mahendra and Virat is `4.002 xx 10^(-7)` N
This is a very small force. If the force of friction between Mahendra and the bench on which he is sitting is zero, then he will start moving towards Virat under the action of this force. We can calculate his acceleration and velocity by using Newton’s laws of motion.