How much volume of carbon dioxide is produced when 50 g of calcium carbonate is heated completely under standard conditions?

Explanation

The balanced chemical equation is,
`CaCO_(3(s)) overset(Delta)to CaO_((s)) +CO_(2(g))`
As per the stoichiometric equation,
1 mole (100g) `CaCO_(3)` on heating produces 1 mole `CO_(2)`

At STP, 1 mole of `CO_(2)` occupies a volume of 22.7 litres
`:.` At STP, 50g of `CaCO_(3)` on heating produces,
`(22.7" litres of " CO_(2))/(cancel(100g underset(2)(CaCO_(3))))xx cancel(50g CaCO_(3))`
=11.35 litres of `CO_(2)`