An ion with mass number 37 possesses unit negative charge. If the ion contains 11.1% more neutrons than electrons. Find the symbol of the ion.

Explanation

Given that, `y=x+11.1%` of x
`=(x+(11.1)/(100)x) =x+0.111x`
`y=1.111x`
mass number = 37
number of protons + number of neutrons = 37
`(x-1) + 1.111x =37`
`x+1.111x =37`
`x+1.111x =38`
`2.111x =38`
`x=(38)/(2.11)`
`x=18.009x =18` (whole number)
`:.` Atomic number `=x-1`
`=18-1=17`
Mass number = 37
Symbol of the ion `""_(17)^(37)Cl^(-)`