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Calculate the molar conductance of 0.025...

Calculate the molar conductance of 0.025M aqueous solution of calcium chloride at `25^(@)C`. The specific conductance of calcium chloride is `12.04 xx 10^(-2) Sm^(-1 )`

Text Solution

Verified by Experts

Molar conductance = `wedge_(m)=(..(sm^(-1))xx10^(-3))/(M) "mol"^(-1) m^(3)`
`=((12.04 xx 10^(-2) Sm^(-1))xx 10^(-3)("mol"^(-1)m^(3)))/(0.025)`
`= 481.6 xx 10^(-2) Sm^(-2) "mol"^(-1)`
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