The number of electrons delivered at the cathode during electrolysis by a current of 1A in 60 seconds is (charge of electron = `1.6xx 10^(-19)` C )

Options

A. `6.22 xx 10^(23)`
B. `6.022 xx 10^(20)`
C. `3.75 xx 10^(20)`
D. `7.48 xx 10^(23)`

Answer

C

Explanation

Q =It
`= 1 A xx 60 `S
96500 C charge `-= 6.022 xx 10^(23)` electrons
60 C charge `-= (6.022xx10^(23))/(96500) xx 960`
`= 3.744 xx 10^(20)` electrons