In the electrochemical cell: ` Zn|ZnSO_(4) (0.01M)||CuSO_(4)(1.0M)|Cu` the emf of this Daniel cell is `E_(1)`. When the concentration of `ZnSO_(4)` is changed to 1.0M and that `CuSO_(4)` changed to 0.01M, the emf changes to `E_(2)`. From the followings, which one is the relationship between `E_(1)` and `E_(2)`?

Options

A. `E_(1) lt E_(2)`
B. `E_(1) gt E_(2)`
C. `E_(2) -0 uarr E_(1)`
D. `E_(1) = E_(2)`

Explanation

`E_("cell")= E_("cell")^(@) - (0.0591)/(2) "log" ([zn^(2+)])/([Cu^(2+)])`
`E_(1) = E_("cell")^(@) - (0.0591)/(2) "log" (10^(2))/(1) " "Zn(s) rarr Zn^(2+) (aq) +2e^(-)`
`E_(1)= E_("cell")^(@) +0.591…………….. (1) " " Zn(s) + Cu^(2+) (aq) rarr Zn^(2+) (aq) +Cu(s)`
`E_(2) = E_("cell")^(@) - (0.0591)/(2) "log" (1)/(10^(-2))`
`E_(2) = E_("cell")^(@) - 0.0591 `
`:. E_(1) gt E_(2)`