0.1M NaCl solution is placed in two different cells having cell constant 0.5 and 0.25 `cm^(-1)` respectively. Which of the two will have greater value of specific conductance

Explanation

Degree of dissociation ` alpha= (wedge^(@))/(wedge_(oo)^(@))`
`wedge_(oo)^(@)= lambda_("cation")^(@) +lambda_("anion")^(@)`
`= ( 248 .2+ 51.8) S cm^(2) mol^(-1)`
`= 300 S cm^(2) mol^(-1)`
`= 300 xx 10^(-14) s m^(2) mol^(-1) `
`alpha = (1.5 xx 10^(-3) S m^(2) mol^(-1))/(300 xx 10^(-4) S m^(2) mol^(-1))`
`alpha = 0.05`
`K_(a) = (alpha^(2)c)/(1 - alpha)`
`= ((0.05)^(2)(0.01))/(1-0.05)`
= `(25xx 10^(-4) xx 10^(-2))/(95 xx 10^(-2)) `
`0.26 xx 10^(-4) `
`= 2.6 xx 10^(-5)`