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The parallax of a heavenly body measured...

The parallax of a heavenly body measured from two points diametrically opposite on equator of earth is 2'. Calculate the distance of the heavenly body. [Given radius of the earth = 6400km] `[1^(n)=4.85 xx 10^(-6)"rad"]`

Text Solution

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By the principle of homogeneity, `a//V^(2)` is of the dimensions of pressure  and b is of the dimensions of volume.
[a] = [pressure] `[V^(2)]= [ML^(-1) T^(-2)] [L^(6)]= [ML^(5)T^(-2)]`
[b] `=[V]= L^(3)`
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