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A body of mass 5kg is thrown up vertical...

A body of mass 5kg is thrown up vertically with a kinetic energy of 1000 J. If acceleration due to gravity is `10ms^(-2)`, find the height at which the kinetic energy becomes half of the original value.

Text Solution

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By the principle of homogeneity, `a//V^(2)` is of the dimensions of pressure  and b is of the dimensions of volume.
[a] = [pressure] `[V^(2)]= [ML^(-1) T^(-2)] [L^(6)]= [ML^(5)T^(-2)]`
[b] `=[V]= L^(3)`
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