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The partial pressure of CH(3) OH (g), C...

The partial pressure of `CH_(3) OH (g), CO_((g))` and `H_(2(g))` in equilibrium mixture for the reaction,
`CO_((g)) +2H_(2(g)) hArr CH_(3)OH` are 2.0, 1.0 and 0.1 atm respectively at `427^(@)C`. The value of `K_(p)` for decomposition of `CH_(3)OH` to CO and `H_(2)` is:

A

`10^(2)"atm"^(2)`

B

`2 xx 10^(2) "atm"^(-2)`

C

`50"atm"^(2)`

D

`5 xx 10^(-3)"atm"^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
`CO_((g)) +2H_(2(g)) to CH_(3)OH(g)`
`K_(P) = (P_(CH_(3) OH))/(P_(CO) xx (P_(H_(2)))^(2)) =(2)/(1xx(0.1)^(2)) = 200" atm"^(-2)`
Thus, `K_(P)` for decomposition of `CH_(3) OH = (1)/(200)`
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