The molar conductivity of a 1.5 M solution of an electrolyte is found to be `138.9 S cm^(2) mol^(-1)`. Calculate the conductivity of the solution.

Options

A. `1.023 S cm^(-1)`
B. `0.026 S cm^(-1)`
C. `0.208 S cm^(-1)`
D. `0.325 S cm^(-1)`

Answer

C

Explanation

Here molar conductivity
`^^_(m)= 1.38. 9s cm^(2) mol^(-1)`
= 1.5 M, conductivity K =?
Molar conductivity, `^^_(m)= (K xx 1000)/("Molarity")`
`138.9= (K xx 1000)/(1.5)`
`K= (138.9 xx 1.5)/(1000)= (208.35)/(1000)= 0.208 S cm^(-1)`