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How much chlorine will be liberated on p...

How much chlorine will be liberated on passing one ampere current for 30 minutes through NaCl solution ?

A

0.66 mole

B

0.33 mole

C

0.66 g

D

0.33 g

Text Solution

Verified by Experts

The correct Answer is:
C
`Cl^(-) to (1)/(2) Cl_(2)+ e^(-)`
w= Zlt
`= (35.5)/(96500) xx 1 xx 30 xx 60= 0.66 g`
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