Two different electrolytic cells filled with molten `Cu(NO_(3))_(2)` and molten `AI(NO_(3))_(3)` respectively are connected in series. When electricity is passed 2.7 g Al is deposited on electrode. Calculate the weight of Cu deposited on cathode. [Cu = 63.5, `Al = 27.0 g mol^(-1)`]

Options

A. 190.5 g
B. 9.525 g
C. 63.5 g
D. 31.75 g

Answer

B

Explanation

`("wt.of Al deposited")/("wt.of Cu deposited")= ("eq.wt.of Al")/("eq.wt.of Cu")`
`(2.7)/("wt.of Cu")= (27//3)/(63.5//2)`
wt.of Cu= 9.525 g