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For a cell reaction, Zn+ Cu^(2+)(aq) t...

For a cell reaction,
`Zn+ Cu^(2+)(aq) to Zn^(2+)(aq)+ Cu`
Cell representation is

A

`Cu^(2+)| Cu || Zn |Zn^(2+)`

B

`Cu^(2+)| Cu || Zn^(2+) |Zn`

C

`Zn|Zn^(2+) || Cu^(2+)| Cu `

D

`Cu^(2+)|Zn || Zn^(2+)| Cu`

Text Solution

Verified by Experts

The correct Answer is:
C

Cell representation is done as follows
Anode | Anodic electrolyte || cathodic electrolyte | cathode
(i) Oxidation is loss of electron and it takes place at anode. Reduction is gain of electron and it takes place at cathode.
`:.` For cell reaction,
`Zn + Cu^(2+) (aq) to Zn^(2+) (aq) + Cu`
Zn is anode and Cu is cathode.
`:.` Cell representation is
`Zn|Zn^(2+) || Cu^(2+)| Cu `
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