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When 9.65 C of electricity is passed thr...

When 9.65 C of electricity is passed through a solution of silver nitrate (atomic weight of Ag = 107.87 taking as 108), the amount of silver deposited is

A

5.8 mg

B

10.8 mg

C

15.8 mg

D

20.8 mg

Text Solution

Verified by Experts

The correct Answer is:
B
`w_(Ag)= (E_(Ag) xx Q)/(96500)= (108 xx 9.65)/(96500)= 1.08 xx 10^(-2) g= 10.8 mg`
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