On passing 0.1 F of electricity through molten solution of. `Al_(2)O_(3)` amount of aluminium metal deposited at cathode is (Al = 27)

Options

A. 0.3 g
B. 0.6 g
C. 0.9 g
D. 1.2 g

Answer

C

Explanation

At cathode,
`Al^(3+) 3e^(-) to Al`
`E_(Al)= (27)/(3)= 9`
`w_(Al)= E_(Al) xx ` no of faradays
= 9 `xx` 0.1 = 0.9 g