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A conductance cell when filled with 0.5 ...

A conductance cell when filled with 0.5 M KCl solution (conductivity =` 6.67 xx 10^(-3)Omega cm^(-1)`) registers a -3 resistance of `243 Omega`. What will be the cell constant?

A

1.62 cm

B

`1.62 cm^(-1)`

C

`1.62 dm^(-1)`

D

`1.62 m^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
Given for KCl,
C = 0.5 M
`kappa= 6.67 xx 10^(-3) Omega^(-1) cm^(-1)`
`R= 243 Omega`
Cell constant
`kappa= (1)/(R)x "cell constant "`
Cell constant
`= kappa xx R = 6.67 xx 10^(-3) xx 243= 1.62 cm^(-1)`
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