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One gram of activated carbon has a surfa...

One gram of activated carbon has a surface area of 1000 m. Considering complete coverage as well as monomolecular adsorption, how much ammonia at 1 atm and 273 K would be adsorbed on the surface of
`(44)/(7) g` carbon if radius of a ammonia molecules is `10^(-8) cm . "[Given , " N_A = 6 xx 10^(23)]`

A

7.46 L

B

0.33L

C

44.8 L

D

23.5L

Text Solution

Verified by Experts

The correct Answer is:
A
Total surface area of carbon =`44/7 xx10^(7) cm^(2) r=10^(-8)` cm
No of `NH_(3)` molecules adsorbed =`((44)/(7)xx10^(7))/((22)/(7)xx10^(-16))=2xx10^(23)`
vol of `NH_(3)` adsorbed at STP =`(2xx10^(23))/(6xx10^(23))xx22.4 =7.46 L`
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