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At 1 atm and 273 K the volume of nitroge...

At 1 atm and 273 K the volume of nitrogen gas required to cover a sample of silica gel, assuming Langinuin monolayer adsorption, is found to be `1.30 cm^3 g^(-1)` of the gel. The area occupied by a nitrogen molecule is `0.16 nm^(2)`. What is the surface area per gram of silica gel?
[Given : `N_A = 6 xx 10^(23)]`

A

5.568 `m^(2) g^(-1)`

B

3.48 `m^(2) g^(-1)`

C

1.6 `m^(2) g^(-1)`

D

2.72 `m^(2) g^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
No of molecules per gram of `N_(2)` in monolayer =`(6xx10^(23))/(22400)xx1.30=3.48 xx10^(19)`
Cross sectional area of a molecule =`1.6 xx10^(-19) m^(2)`
`therefore` surface area =`5.568 m^(2) g^(-1)`
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