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50 mL of 0.3 Macetic acid is shaken with...

50 mL of 0.3 Macetic acid is shaken with 5 g activated charcoal. The concentration of acetic acid is reduced to 1/3 of original molarity. The mass of acetic acid adsorbed per g of charcoal

A

`2xx10^(-4)` g

B

0.12g

C

`2xx10^(-2)` g

D

`3xxl0^(-2)` g

Text Solution

Verified by Experts

The correct Answer is:
B
Initial mole =`50xx0.3=15` mole left after adsorption =`50xx0.3xx1/3=5`
mole adsorbed per g =`(10xx10^(-3))/(5) =2xx10^(-3)`
mass adsorbed per `g=2xx10^(-3) xx60=120xx10^(-3)=0.12 g`
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