Home
Class 12
CHEMISTRY
Assertion: In the coagulation of a negat...

Assertion: In the coagulation of a negative sol the flocculationg power is in the order:
`Al^(3+)gtBa^(2+)gtNa^(+)`
Reason: Greater the valence of the flocculating ion added, greater is its power to cause precipitation.

A

If both (A) and (R) are correct, and (R) is the correct explanation of (A)

B

If both (A) and (R) are correct, but (R) is not the correct explanation of (A)

C

If (A) is correct, but (R) is incorrect

D

If (A) is incorrect, but (R) is correct

Text Solution

Verified by Experts

The correct Answer is:
A

This is Hardy-Schulze rule.
Promotional Banner

Similar Questions

Explore conceptually related problems

In the coagulation of a positive sol, the flocculating power of the ions PO_(4)^(3-), SO_(4)^(2-) and Cl^(-) decreases in the order

The existence of charge on colloidal particles is confirmed by electrophoresis experiment. In the coagulation of,a negative sol, the coagulating power is in the order AI^(3+) > Ba(2+) > Na^+ . Name and state the rule behind this?

Among the anions Cl^(-),SO_(4)^(-2),PO_(4)^(-3) , the coagulating power follows the order

The Ion which is more effective for the coagulation of negative sol As_2S_3 is ?

Assertion : For the coagulation of sols carrying positive charege PO_(4)^(3-) ions are more efficient than SO_(4)^(2-) or CI^(-) ions Reason : This follows Hardy schulze rule

The coagulating powers of electrolytes having ions Na^(+), Al^(3+) and Ba^(2+) for arsenic sulphides sol increases in the order

Assertion: Na^(+) and Al^(3+) are isoelectronic but the magnitude of the ionic radius of Al^(3+) is less than that of Na^(+) Reason: The magnitude of effective nuclear charge of the outer shell electrons in Al^(3+) is greater than in Na^(+)

Assertion : MnO is basic whereas Mn2O7, is acidic. Reason : Higher the oxidation state of a transition metal in its oxide, greater is the acidic character.