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A photon of wavelength 450 nm strikes a ...

A photon of wavelength 450 nm strikes a metal surface whose work function is 2.5 eV. Calculate
the energy of the photon

Text Solution

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i) Energy of the photon, `E=(hc)/(lambda)=(6.626xx10^(-34)Js xx 3.0 xx 10^(8)ms^(-1))/(450xx10^(-9)m) =4.4 xx 10^(-19)J`
ii) `KE=hv-W_(0)=4.4 xx 10^(-19)J-(2.5eV xx 1.6xx10^(-19) JeV^(-1)) =4.0xx10^(-18)J`
iii) `KE=(1)/(2)mv^(2) rArr v^(2)=(2xx KE)/(m) rArr v= sqrt((2KE)/(m))= sqrt((2xx4.0xx10^(-18)J)/(9.1xx10^(-31)))=2.96 xx 10^(6)ms^(-1)`
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