A 1kW radio transmitter operates at a frequency of 880 Hz. How many photons per second does it emit?

Options

A. `1.71 xx 10^(-21)`
B. `1.71 xx 10^(33)`
C. `6.02 xx 10^(23)`
D. `2.85xx10^(28)`

Answer

B

Explanation

For 1 kW ratio transmitter, the energy is given by `E=nhv =1000J s^(-1)`
Given that `v=880 s^(-1) and h=6.62 xx 10^(-34)Js`
Substituting in the above equation, we get the number of photons emitted per second
`n=(1000)/((880s^(-1)) xx (6.62 xx 10^(-34)Js)) =(1000)/(5.831xx10^(-31))=1.717xx10^(33)`