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Energy of an electron is given by, E=-2....

Energy of an electron is given by, `E=-2.178 xx10^(-18) 4 ((Z^(2))/(n^(2))) J.` Wavelength of light required to excite an electron in hydrogen atom from level n = 1 to n = 2 will be: `(h = 6.62 xx 10^(-34) J s and c = 3 xx 10^(8) ms^(-1))`

A

`6.500xx10^(-7)m`

B

`8.500 xx 10^(-7)m`

C

`1.214 xx 10^(-7)m`

D

`2.816 xx 10^(-7)m`

Text Solution

Verified by Experts

The correct Answer is:
C
`DeltaE= (E_(2)-E_(1))`
`"h"(c )/(lambda)=((-2.178xx10^(-18))/(4)) -((-2.178xx10^(-18))/(1))`
`(6.62 xx 10^(-34)xx3xx10^(8))/(lambda)=2.178xx10^(-18) [1-(1)/(4)]`
`lambda=(6.62xx10^(-34)xx3xx10^(8)xx4)/(3xx2.178xx10^(-18)) =1.214xx10^(-7)m`
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