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The orbital angular momentum of an elect...

The orbital angular momentum of an electron in a d-orbital is :

A

`sqrt(6)(h)/(2pi)`

B

`sqrt(2)(h)/(2pi)`

C

`(h)/(2pi)`

D

`(2h)/(2pi)`

Text Solution

Verified by Experts

The correct Answer is:
A
Orbitals angular momentum `=sqrt(l(l+1))(h)/(2pi)= sqrt(2(2+1))=(h)/(2pi) = sqrt(6) (h)/(2pi)" "` (Here, `l=2`, for d-orbitals)
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