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Light of frequency 6 xx 10^(14) Hz is in...

Light of frequency `6 xx 10^(14)` Hz is incident on a metal whose work function is 2eV `(h=6.63 xx 10^(-34) Js,leV =1.6 xx 10^(-19)J)`. The maximum energy of electrons emitted will be:

A

2.49eV

B

4.49 eV

C

0.49 eV

D

5.49eV

Text Solution

Verified by Experts

The correct Answer is:
C
Absorbed energy = thereshold energy + K.E. photo electron
Energy of light `=hv =6.626 xx 10^(-34)xx6xx10^(14)=3.9756xx10^(-19)J=(3.9756xx10^(-19))/(1.6xx10^(-19))=2.49eV`
Kinetic energy of photoelectron `=(2.49-2.0)eV=0.49eV`
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