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If the electronic configuration of nitro...

If the electronic configuration of nitrogen had `1s^(7)`, it would have energy lower than that of the normal ground 'state configuration `1s^(2)2s^(2)2p^(3)` because the electrons would be closer to the nucleus. Yet `1s^(7)` is not observe because it violates:

A

Heisenberg uncertainty principle

B

Hund's rule

C

Paul's exclusion priciple

D

Bohr postulates of stationary orbits

Text Solution

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The correct Answer is:
C
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