A block of mass M is pulled along a horizontal smoooth surface by a rope of mass m. Force P is applied at one extremity of the rope. The force exerted by the rope on the block is

Options

A. `P(M+m)`
B. `P(M-m)`
C. `(PM)/((M+m))`
D. `(PM)/((M-m))`

Answer

C

Explanation

Acceleration of block `= ("Force")/("Total mass") therefore a= (P)/((M+m))`
`therefore` Force on block= (Mass of block) `xx` (Acceleration a) `=(PM)/((M+m))`