A body of weight 64N is pushed with just enough force to start it moving. Cross a horizontal floor and he same force continues to act afterwards. If the coefficients of static and dynamic friction are 0.6 and 0.4 respectively, the acceleration of the body will be (Acceleration due to gravity =g)

Options

A. `(g)/(6.4)`
B. `0.64g`
C. `(g)/(32)`
D. `0.2g`

Answer

D

Explanation

`F_(l) = mu_(s)R rArr 64= 0.6mg, m = (64)/(0.6g)`
`a= ("Applied force- Kinetic friction")/("Mass of the body")= (64-mu_(K) mg)/(m)= (64 - 0.4 xx (64)/(0.6))/((64)/(0.6g))= 0.2g`