A mass of 10kg is suspended by a rope of length 2m from a ceiling. A force of 75N is applied in the horizontal direction at the mid-point of the rope. The angle made by the rope, with the vertical, in equilibrium position will be (Take `g= 10 ms^(-2)`, neglect the mass of the rope)

Options

A. `47^(@)`
B. `38.5^(@)`
C. `45^(@)`
D. `37^(@)`

Answer

D

Explanation

`(75)/(SA) = (10 xx 10)/(SB) rArr (SA)/(SB)= (3)/(4) or tan theta = (SA)/(SB)= (3)/(4) = tan 37^(@) therefore theta= 37^(@)`