A body of 10kg is kept pressing normally on an inclined plane of inclination `30^(@)` by a force of 200N. The coefficient of static friction between the plane and the body is 0.3. Then the frictional force is equal to

Options

A. 100N
B. 50N
C. 200N
D. 300N

Answer

B

Explanation

`F= mg sin theta= 10 xx 10 xx (1)/(2) = 50N`