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Four charges +q,-q,-2q and +2q are kept ...

Four charges `+q,-q,-2q and +2q` are kept in the corners of a square of side a. The total field at the centre is

A

`((6sqrt(2)q)/(4piepsilon_(0)a^(2)))hati`

B

`((6sqrt(2)q)/(4piepsilon_(0)a^(2)))hatj`

C

zero

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A


`vecE_(1)=(E_(1)cos45^(@))hati+(E_(1)sin45^(@))hatj`
`vecE_(2)=(E_(2)cos45^(@))hati+(E_(2)sin45^(@))hatj`
`vecE_(R)=2(E_(1)cos45^(@)+E_(2)cos45^(@))hati=sqrt(2)(E_(1)+E_(2))hati, vecE_(R)=sqrt(2)(E_(1)+E_(2))hati`
`E_(1)=(1)/(4piepsilon_(0))(q)/(r^(2)),r=(a)/(sqrt(2)),E_(1)=(2q)/(4piepsilon_(0)a^(2)),E_(2)=(4q)/(4piepsilon_(0)a^(2)),E_(R)=(6sqrt(2)q)/(4piepsilon_(0)a^(2))hati`
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