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Two equal negative charges -q are fixed ...

Two equal negative charges `-q` are fixed at points (0, a) and (0, -a). A positive charge Q is released from result at the point (2a, 0) on the X-axis. The charge Q will ………………

A

move to the origin and remain at rest there

B

execute simple harmonic motion about the origin

C

move to infinity

D

execute osicllations but not simple harmonic motion

Text Solution

Verified by Experts

The correct Answer is:
D


Force exerted by charges `-q` at A and B, `F=(kQq)/(r^(2))`
Resultant is along the x-direction towards the origin `F^(2)=F^(2)+F^(2)+2F^(2)costheta=2F^(2)(1+costheta)`
`Fprop(1)/(r^(2))`
Q will oscillate but motion is not SHM
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