A charge q is divided into three equal parts and placed symmetrically on a circle of radius r. The same charge is divided into four equal parts and placed symmetrically on the same circle. The electric field intensities at the centre of the circle in two situations are zero.
If a charge (part charge) is removed from one location in both the situations, the ratio of magnitudes of the electric field intensities at the centre is

Options

A. `(1)/(2)`
B. `(1)/(1)`
C. `(2)/(3)`
D. `(4)/(3)`

Answer

D

Explanation

When one charge is removed, the field intensity at the centre is due to the removed charge only.
`E_(1)=(1)/(4piepsilon_(0))(q//3)/(r^(2))`
`E_(2)=(1)/(4piepsilon_(0))(q//4)/(r^(2))`
`therefore (E_(1))/(E_(2))=(4)/(3)` `therefore (E_(1))/(E_(2))=(4)/(3)`