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int (0) ^(pi//2) e ^(x) cos xdx is equal...

`int _(0) ^(pi//2) e ^(x)` cos xdx is equal to

A

`(1)/(2) (e -1)`

B

`(1)/(2) (e ^(x) -1)`

C

`(1)/(2) (e ^(pi//2)-1)`

D

`(1)/(2) (1 - e ^( pi//2))`

Text Solution

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The correct Answer is:
C
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