Home
Class 12
PHYSICS
A drop of liquid of density p is floatin...

A drop of liquid of density p is floating half-immersed in a liquid of density d. If σ is the surface tension, then the diameter of the drop of the liquid is

A

`sqrt((sigma)/(g(2rho-d)))`

B

`sqrt((2sigma)/(g(2rho-d)))`

C

`sqrt((8sigma)/(g(2rho-d)))`

D

`sqrt((12sigma)/(g(2rho-d)))`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

A drop of liquid of density rho is floating half-immersed in a liquid of density d . If rho is the surface tension the diameter of the drop of the liquid is

A drop of liquid of density rho is floating half-immersed in a liquid of density d . If rho is the surface tension the diameter of the drop of the liquid is

A solid of density D is floating in a liquid of density d. If upsilon is the volume of solid submerged in the liquid and V is the total volume of the solid, then upsilon//V equal to

A solid of density D is floating in a liquid of density d. If V is the volume of solid submerged in the liquid and V is the total volume of the solid, then V//V is equal to

An object of mass m is floating in a liquid of density sigma . If the object is made up of density rho , then appare weight of the object in the liquid is

A body of volume V and density d is completely immersed in a liquid of density p. Then the apparent weight of the body will be:

If an object of volume V and density d_1 is immersed in a liquid of density d_2 and volume of the liquid displaced is v, then the relation between them is given by the expression__= ___.