Home
Class 12
PHYSICS
A particle moves in one dimension. Its v...

A particle moves in one dimension. Its velocity is given by `v (t)= c _(2)t ^(2) + c _(1) t + c _(0)` where ` c _(1) and c _(2)` are constants. What is the acceleration of the particle at time t = 1?

A

`C _(1) + 2 c _(2)`

B

zero

C

`c _(1) + c _(2)`

D

`C _(1)`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

The displacement of a particle is given by x=a_(0)+(a_(1)t)/(3)-(a_(2)t^(2))/(2) where a_(0),a_(1) and a_(2) are constants. What is its acceleration ?

The displacement x of a particle at time t moving along a straight line path is given by x^(2) = at^(2) + 2bt + c where a, b and c are constants. The acceleration of the particle varies as

The velocity of a particle is given by v=12+3(t+7t^2) . What is the acceleration of the particle?

The velocity upsilon of a particle as a function of its position (x) is expressed as upsilon = sqrt(c_(1)-c_(2)x) , where c_(1) and c_(2) are positive constants. The acceleration of the particle is

A particle moves in a circle of radius 20 cm. Its linear speed is given by v = (3t^(2) +5t) where t is in second and v is in m/s. Find the resultant acceleration at t = 1s.

A particle moves in circle of radius 1.0 cm at a speed given by v=2.0 t where v is in cm/s and t in seconeds. A. find the radia accelerationof the particle at t=1 s. b. Findthe tangential acceleration at t=1s. c.Find the magnitude of the aceleration at t=1s.

If velocity of a particle is given by v=2t^(2)-2 then find the acceleration of particle at t = 2 s.

If velcotiy of a particle is given by v=2t-1 then find the acceleration of particle at t = 2s.

A particle is moving along the path given by y=(C )/(6)t^(6) (where C is a positive constant). The relation between the acceleration ( a ) and the velocity ( v ) of the particle at t=5sec is