Shown here are expressions given to Seema, Anees , Asha and Tessy with their answers
Seema `4 xx 1 + 8 div 2 = 8`
Anees `6 + 4 div 2 -1 = 4`
Asha `9 + 3 xx 2- 4 div 2 = 10`
Tessy `27 div 3 - 2 xx 3 = 21`
Who has got the correct answer ?

Options

A. Asha
B. Tessy
C. Seema
D. Anees

Answer

To determine who has the correct answer among Seema, Anees, Asha, and Tessy, we need to evaluate each expression step by step.

### Step 1: Evaluate Seema's Expression
**Expression:** \( 4 \times 1 + 8 \div 2 \)

1. **Calculate \( 8 \div 2 \)**:
\[ 8 \div 2 = 4 \]

2. **Now substitute back into the expression**:
\[ 4 \times 1 + 4 \]

3. **Calculate \( 4 \times 1 \)**:
\[ 4 \times 1 = 4 \]

4. **Now add the results**:
\[ 4 + 4 = 8 \]

**Seema's answer is correct: \( 8 = 8 \)**.

### Step 2: Evaluate Anees's Expression
**Expression:** \( 6 + 4 \div 2 - 1 \)

1. **Calculate \( 4 \div 2 \)**:
\[ 4 \div 2 = 2 \]

2. **Now substitute back into the expression**:
\[ 6 + 2 - 1 \]

3. **Calculate \( 6 + 2 \)**:
\[ 6 + 2 = 8 \]

4. **Now subtract 1**:
\[ 8 - 1 = 7 \]

**Anees's answer is incorrect: \( 7 \neq 4 \)**.

### Step 3: Evaluate Asha's Expression
**Expression:** \( 9 + 3 \times 2 - 4 \div 2 \)

1. **Calculate \( 4 \div 2 \)**:
\[ 4 \div 2 = 2 \]

2. **Now substitute back into the expression**:
\[ 9 + 3 \times 2 - 2 \]

3. **Calculate \( 3 \times 2 \)**:
\[ 3 \times 2 = 6 \]

4. **Now substitute back**:
\[ 9 + 6 - 2 \]

5. **Calculate \( 9 + 6 \)**:
\[ 9 + 6 = 15 \]

6. **Now subtract 2**:
\[ 15 - 2 = 13 \]

**Asha's answer is incorrect: \( 13 \neq 10 \)**.

### Step 4: Evaluate Tessy's Expression
**Expression:** \( 27 \div 3 - 2 \times 3 \)

1. **Calculate \( 27 \div 3 \)**:
\[ 27 \div 3 = 9 \]

2. **Now substitute back into the expression**:
\[ 9 - 2 \times 3 \]

3. **Calculate \( 2 \times 3 \)**:
\[ 2 \times 3 = 6 \]

4. **Now substitute back**:
\[ 9 - 6 \]

5. **Now subtract**:
\[ 9 - 6 = 3 \]

**Tessy's answer is incorrect: \( 3 \neq 21 \)**.

### Conclusion
The only correct answer is from Seema:

**Seema's Expression: \( 4 \times 1 + 8 \div 2 = 8 \) is correct.**