Home
Class 9
MATHS
ar(DRC) = ar(DPC) and ar(BDP) = ar(ARC)....


ar(DRC) = ar(DPC) and ar(BDP) = ar(ARC). Show that both the quadrilaterals ABCD and DCPR are trapeziums.

Promotional Banner

Topper's Solved these Questions

  • AREAS OF PARALLELOGRAMS AND TRIANGLES

    SWAN PUBLICATION|Exercise EXERCISE 9.4|21 Videos
  • AREAS OF PARALLELOGRAMS AND TRIANGLES

    SWAN PUBLICATION|Exercise OBJECTIVE TYPE QUESTIONS |20 Videos
  • AREAS OF PARALLELOGRAMS AND TRIANGLES

    SWAN PUBLICATION|Exercise EXERCISE 9.2|8 Videos
  • CIRCLES

    SWAN PUBLICATION|Exercise Objective Type Questions (Fill in the Blanks :)|10 Videos

Similar Questions

Explore conceptually related problems

Diagonals AC and BD of a quadrilateral ABCD intersect at O in such a way that ar (AOD) = ar (BOC). Prove that ABCD is a trapezium.

The area of the parallelogram ABCD is 90 cm^2 Find ar(ABD)

The area of the parallelogram ABCD is 90 cm^2 Find ar(BEF)

If ar(||gm ABCD) = 252 cm^2 , then find the area of triangleADB ?

The area of the parallelogram ABCD is 90 cm^2 Find ar(ABEF)

ABCD, DCFE and ABFE are parallelograms. Show that ar(ADE) = ar(BCF)

E is any point on median AD of a triangle ABC . Show that ar (ABE) = ar (ACE).

In the figure. ABCD is a parallelogram and O is any point on BC . Prove that ar (triangleABO) + ar (triangleDOC) = ar(triangleODA)

ABCD is a tetrahedron such that each of the triangleABC , triangleABD and triangleACD has a right angle at A. If ar(triangleABC) = k_(1). Ar(triangleABD)= k_(2), ar(triangleBCD)=k_(3) then ar(triangleACD) is

In Fig. 9.13, ABCD is a parallelogram and EFCD is a rectangle. Also, AL bot DC . Prove that (i) ar (ABCD) = ar (EFCD) (ii) ar (ABCD) = DC × AL

SWAN PUBLICATION-AREAS OF PARALLELOGRAMS AND TRIANGLES -EXERCISE 9.3
  1. E is any point on median AD of a triangle ABC . Show that ar (ABE) = a...

    Text Solution

    |

  2. Show that the diagonals of a parallelogram divide it into four triangl...

    Text Solution

    |

  3. In Fig ., ABC and ABD are two triangles on the same base AB ....

    Text Solution

    |

  4. D, E and F are respectively the mid-points of the sides BC, CA and AB ...

    Text Solution

    |

  5. D, E and F are respectively the mid-points of the sides BC, CA and AB ...

    Text Solution

    |

  6. D, E and F are respectively the mid-points of the sides BC, CA and AB ...

    Text Solution

    |

  7. In Fig ., diagonals AC and BD of quadrilateral ABCD intrsect at...

    Text Solution

    |

  8. In Fig ., diagonals AC and BD of quadrilateral aBCD intrsect at...

    Text Solution

    |

  9. In Fig ., diagonals AC and BD of quadrilateral ABCD intrsect at...

    Text Solution

    |

  10. D and E are points on sides AB and AC respectively of DeltaABC such th...

    Text Solution

    |

  11. XY is a line parallel to side BC of triangle ABC. If BE II AC and CF I...

    Text Solution

    |

  12. The side AB of a parallelogram ABCD is produced to any point P. A line...

    Text Solution

    |

  13. In the figure. ABCD in a trapezium in which AB||DC. Proe that ar(trian...

    Text Solution

    |

  14. In Fig ., ABCDE is a pentagon . A line through B parallel to ...

    Text Solution

    |

  15. In Fig ., ABCDE is a pentagon . A line through B parallel to ...

    Text Solution

    |

  16. Find the area of a square plot of side 8m.

    Text Solution

    |

  17. ABCD is a trapezium with AB || DC. A line parallel to AC intersects AB...

    Text Solution

    |

  18. In Fig ., AP||BQ ||CR . Prove that ar (DeltaPBR) = ar (DeltaAQC)

    Text Solution

    |

  19. Diagonals AC and BD of a quadrilateral ABCD intersect at O in such a w...

    Text Solution

    |

  20. ar(DRC) = ar(DPC) and ar(BDP) = ar(ARC). Show that both the quadrilate...

    Text Solution

    |