A train starting from a railway station and moving with uniform acceleration attains a speed 40 km `h^(-1)`in 10 minutes. Find its acceleration.

Explanation

Here,
Initial velocity of the train , u = 0
Final velocity of the train, `v = 40 km h^(-1)`
`=(40xx1000)/(60xx60)ms^(-1)`
Time, t = 10 minutes=`100/9ms^(-1)`
`=10xx60s=600s `
Let acceleration of the train = a = ?
Using v = u + at, we get
`a=(v-u)/t=(100/9-0)/600ms^(-2)`
`=100/(9xx600)ms^(-2)=1/54ms^(-2)`